C++ 随笔
Written on March 24th, 0221 by Kong Wei Hang- 虚析构函数是可以声明的,这意味着需要由于子类来实现接口的析构函数。 reference: https://blog.csdn.net/wufeifan_learner/article/details/88804072 ```C++
class A{ public: A(){ cout«“构造函数A”«endl; } virtual ~A() = 0; };
class B: public A{ public: B(){ cout«“构造函数B”«endl; } ~B(){ //TODO }
```
- 待续
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